How many 2 digit numbers are divisible by 3?

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We know that the first two digit numbers are divisible by 3 is 12 and the last two digit numbers divisible by 3 is 99.

Thus, we get

12,15,18,…,99 which is an AP.

Here, a=12,d=3

Let there be n terms. Then,

an =99

a+(n−1)d=99

12+(n−1)3=99

n=29+1=30

Therefore, the two digit numbers divisible by 3 are

30.